a area of rectangle room is 212 sqm. If it length is 70m .find its perimeter ?plz send ans fast
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Answered by
1
Given:-
Length = 70 m
Area of rectangle = 212 m²
l × b = 212 m²
70 × b = 212 m²
b = 212/70
b = 3.02 m
Now,
Perimeter = 2(l+b)
Perimeter = 2(70+3.02)
Perimeter = 2 × 73.02 m
Perimeter = 146.04 m
Answered by
0
Answer:
area of rectangle =length×breadth
area=212 Square metre
length=70m
breadth =x
area=l×b
212=70×(×)
212=70×
×=212/70
×=3.028
breadth =3.028
perimeter of rectangle =2(l+b)
l=70
b=3.028
perimeter of rectangle =2(70+3.028)
2(73.028)
146.056m
hence perimeter of rectangle is 14.056m
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