Math, asked by rithickprasannaa, 8 months ago

a area of rectangle room is 212 sqm. If it length is 70m .find its perimeter ?plz send ans fast​

Answers

Answered by aaravshrivastwa
1

Given:-

Length = 70 m

Area of rectangle = 212 m²

l × b = 212 m²

70 × b = 212 m²

b = 212/70

b = 3.02 m

Now,

Perimeter = 2(l+b)

Perimeter = 2(70+3.02)

Perimeter = 2 × 73.02 m

Perimeter = 146.04 m

Answered by muskan3876
0

Answer:

area of rectangle =length×breadth

area=212 Square metre

length=70m

breadth =x

area=l×b

212=70×(×)

212=70×

×=212/70

×=3.028

breadth =3.028

perimeter of rectangle =2(l+b)

l=70

b=3.028

perimeter of rectangle =2(70+3.028)

2(73.028)

146.056m

hence perimeter of rectangle is 14.056m

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