A area of right triangle is 480 cm^ if the base of the triangle is 8 cm more than twice the height of the triangle then find the sides of the triangle
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let the base=b
b-8=2h. {h=hight}
h=(b-8)/2
480 = 1/2×b×(b-8)/2
480×4=b(b-8)
b^2-8b-1920=0
b=48
b-8=2h. {h=hight}
h=(b-8)/2
480 = 1/2×b×(b-8)/2
480×4=b(b-8)
b^2-8b-1920=0
b=48
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