Math, asked by sakshigujral820, 1 year ago

A as 75% more efficient than b in how many days can a and b working together complete a piece of work which a alone takes 12 days finsh

Answers

Answered by mkrishnan
1

Answer:

THEY COMPLETE IN     84/11 = 7  7/11 DAYS  

Step-by-step explanation:

let  B can  complete in  d    days

one day work done by B    = 1/d

A as 75% more efficient than B

One day work done by A    = 1/d + 75/[100]d

                                             =1/d  +3/[4d]

A can  complete in   12   days

One day work done by A  = 1/12

1/d  +3/[4d] =1/12

4/4d +3/4d =1/12

7/4d =1/12

7x12/4 =d

d =21

B can   complete in  21    days

One day work done by A and B = 1/12+1/21 =7/84 +4/84 =11/84

THEY COMPLETE IN     84/11 = 7  7/11 DAYS  

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