Question

a. Assume, a person is standing in front of a plane mirror. The distance between
the mirror and his image is 6 m. If the person moves 2 m towards the
plane mirror, what would be the distance between the person and his image?
b. The angle formed between incident ray and normal is 60 degree and then
what will be the angle between reflected ray and normal? ​

Answer 1

Explanation:

a) IN A PLANE MIRROR OBJECT DISTANCE AND IMAGE DISTANCE ARE EQUAL.

THAT IS X=Y

X IS THE DISTANCE OF IMAGE FROM MIRROR

Y IS THE DISTANCE OF OBJECT FROM MIRROR

GIVEN: X=6 M SO Y= 6 M

THEREFORE TOTAL DISTANCE BETWEEN OBJECT AND IMAGE IS X+Y= 6M+6M =12M

NOW,

AS PER THE GIVEN QUESTION THE PERSON MOVES 2M TOWARDS THE MIRROR

THEN X=Y=6M–2M = 4M

THUS THE NEW DISTANCE BETWEEN THE IMAGE AND THE PERSON WOULD BE 4M + 4M= 8M.