A athelete complete one round of a circular track of radius 10 m in 40 sec .The distance cover by him in 2 min 20 sec is
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Time in seconds=2×60+20=140sec
Circumference=2πr
=2π(10). (Given r=10m)
=62.83m
No. Of rounds completed by him in 140sec = 140/40 =3.5
Therefore total distance covered covered by him = no. of rounds×circumference =3.5×62.83
=219.91 m
It is approximated to 220 m.
Hope it helps.
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Circumference=2πr
=2π(10). (Given r=10m)
=62.83m
No. Of rounds completed by him in 140sec = 140/40 =3.5
Therefore total distance covered covered by him = no. of rounds×circumference =3.5×62.83
=219.91 m
It is approximated to 220 m.
Hope it helps.
Pls mark it as the brainliest.
tejasreee:
Thanks
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