a/ax-1+b/bx-1=a+b please solve this question and take out the value of x
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Answer:
x = 2/( a+b-ab)
Step-by-step explanation:
The value of x is 2/a+b-ab.
Solution: a/ax-1 + b/bx-1 = a+b
(abx - a +abx-b)/(ax-1)(bx-1) = a+b
2abx - a - b = (a+b)(abx^2 - ax - bx +1)
2abx - a - b = a^2bx^2 - a^2x - abx + a + ab^2x^2 - abx - b^2x + b
x(2ab - a^2b + a^2 - ab^2 + b^2) = 2a + 2b
x[(a+b)^2 - a^2b - ab^2] = 2a+2b
x = 2(a+b)/(a+b)(a+b-ab)
x = 2/( a+b-ab)
Hope this helps.
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