Math, asked by pawanrai39, 11 months ago

a/ax-1+b/bx-1=a+b please solve this question and take out the value of x​

Answers

Answered by Indianpatriot
1

Answer:

x = 2/( a+b-ab)

Step-by-step explanation:

The value of x is 2/a+b-ab.

Solution: a/ax-1 + b/bx-1 = a+b

(abx - a +abx-b)/(ax-1)(bx-1) = a+b

2abx - a - b = (a+b)(abx^2 - ax - bx +1)

2abx - a - b = a^2bx^2 - a^2x - abx + a + ab^2x^2 - abx - b^2x + b

x(2ab - a^2b + a^2 - ab^2 + b^2) = 2a + 2b

x[(a+b)^2 - a^2b - ab^2] = 2a+2b

x = 2(a+b)/(a+b)(a+b-ab)

x = 2/( a+b-ab)

Hope this helps.

Answered by Anisha5119
2

Answer:

VERIFIED ANSWER

MARK AS BRAINLIEST AND GIVE ❤️

Attachments:
Similar questions