Question

A+b=0 c+b=0 what is cube od c

Answer 1

See,

If a + b + c = 0

Then,

a + b + c = 0

a + b = - c -- (I)

(a + b)^3 = (- c)^3

a^3 + b^3 + 3ab (a + b) = - c^3

from equation (I) a + b = - c

a^3 + b^3 + 3ab (- c) = - c^3

a^3 + b^3 - 3abc = - c^3

a^3 + b^3 + c^3 = 3abc

Hence,

a^3 + b^3 + c^3 ‘not equal’ 0

but,

a^3 + b^3 + c^3 ‘equal’ 3abc







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Answer 2

Answer:

Zee-row! (zero - 0)

Step-by-step explanation:

a + b = 0

b = -a --- (1)

Substituting (1) in c + b = 0, we get:

c + (-a) = 0

c - a = 0

-1(c - a) = 0

-c + a = 0

a - c = 0

a = c --- (A)

a + b = 0

a = 0/b

a = 0 --- (2)

Substituting (2) in the same a + b = 0

a + b = 0

(0) + b = 0

b = 0

(A) --- a = c

a = 0

c = a

c = 0

c³ = 0³

c³ = 0

There, you got your answer!

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