(a+b) ^-1×(a^-1+b^-1) = a^x b^y find x+y+2
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I'm trying to prove the below equation, where a,b∈G and (G,∗) is a group.
(a∗b)−1=(a−1)∗(b−1)
I'm not really sure how to do it though. I tried doing something like
(a∗b)−1∗(a∗b)=e=a∗a−1∗b−1∗b
(a∗b)−1∗(a∗b)=e=a∗(a−1∗b−1)∗b
However, I can't get the RHS to (a∗b)∗(a−1∗b−1) without assuming communitivity.
How would I go about doing this? Any help is appreciated.
Thanks
Edit: Given that correction, would this be correct?
(a∗b)−1∗(a∗b)=e=a∗(b∗b−1)∗a−1
Then
a∗(b∗b−1)∗a−1=a∗b∗(b−1∗a−1)=(a∗b)∗(b−1∗a−1)
Thus
(a∗b)−1=(b−1∗a−1)
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hope this helps uh dear❤❤❤❤❤☹
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