a+b=1 a-b=7 find a^2+b^2
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Answered by
10
a+b=1........(1)
a-b=7........(2)
(2)/(1),2a=8
a=4
b=-3
a²+b²=4²+(-3)²=16+9=25
plzzzz mark as brainliest...
a-b=7........(2)
(2)/(1),2a=8
a=4
b=-3
a²+b²=4²+(-3)²=16+9=25
plzzzz mark as brainliest...
Answered by
8
Hey !
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Given -> a + b = 1
↪a - b = 7
Solution -> By subtracting both equations
↪b = -3
↪Put value of b in
↪a - b = 7
↪a - (-3) = 7
↪a + 3 = 7
↪a = 7 - 3 = 4
↪a = 4
↪a^2 + b^2
↪(4)^2 + (-3)^2
↪16 + 9 = 25
_____________________________________
__________________________________
Given -> a + b = 1
↪a - b = 7
Solution -> By subtracting both equations
↪b = -3
↪Put value of b in
↪a - b = 7
↪a - (-3) = 7
↪a + 3 = 7
↪a = 7 - 3 = 4
↪a = 4
↪a^2 + b^2
↪(4)^2 + (-3)^2
↪16 + 9 = 25
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honeybee05:
ur answer is wrong
It's correct :-))
no
the answer is 25
u have written 25 but the answer had reached half so i thought it was wrong
sry
It's OK :-))
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