Math, asked by atomSTUDY, 1 year ago

A+B=1 ; B+2C=0 ; A-B+C=2 . Find values of A,B,C. Please give answer fast with derivation.​

Answers

Answered by abhi14366
0

Answer:

a+b=1,a=b-1(1)

b=a-1(2)

b+2c=0

b=2c

c=b/2(3)

Step-by-step explanation:

b=b-1-1( from eq 1 and 2)

b=b-2

c=b-2/3

Answered by ashokraipilli1729
1

Answer:

a+b=1

2(b+2c=0)

a-b+c=2

a+b-(a-b+c)=1-2

2b+c=-1

2b+4c=0

c=1/3

b=-2/3

a=1/3

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