a+b=1 b+c=2 c+d=3 find a+d
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Step-by-step explanation:
From ab = 1 we have b = 1/a.
From bc = 2 we have c = 2/b, substituting b = 1/a we have that c = 2a.
From cd = 3 we have d = 3/c, substituting c = 2a we have that d = 3/2a.
From de = 4 we have e = 4/d, substituting d = 3/2a we have e = 8a/3.
Since ea = 6 and e = 8a/3 we find 8a 2/3 = 6, solving for a, we have a = 3/2.
From this b = 1/a = 2/2, c = 2a = 3, d = 3/2a = 1 and e = 8a/3 = 4.
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a+b= 1 ...... b= 1-a...
b+c= 2 ...... c= 2-b== 2-1+a = 1+a
c+d= 3....... d= 3-c== 3-1-a = 2-a.
a+d = ?
thus, a+ 2-a = 2
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