Question

a+b=1 b+c=2 c+d=3 find a+d​

Answer 1

Answer:

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Step-by-step explanation:

From ab = 1 we have b = 1/a.

From bc = 2 we have c = 2/b, substituting b = 1/a we have that c = 2a.

From cd = 3 we have d = 3/c, substituting c = 2a we have that d =  3/2a.

From de = 4 we have e = 4/d, substituting d = 3/2a we have e = 8a/3.

Since ea = 6 and e = 8a/3 we find  8a 2/3 = 6, solving for a, we have a = 3/2.

From this b = 1/a = 2/2, c = 2a = 3, d = 3/2a = 1 and e = 8a/3 = 4.

Answer 2

a+b= 1 ...... b= 1-a...

b+c= 2 ...... c= 2-b== 2-1+a = 1+a

c+d= 3....... d= 3-c== 3-1-a = 2-a.

a+d = ?

thus, a+ 2-a = 2