(a+b)(1-c)-(b+c)(1-a) linear equation
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Answer:
Step-by-step explanation:
For A(1,2), we have 2=9(1)−7=9−7=2
For B((−1,−16), we have -16=9(−1)−7=−9−7=−16
For C(0,−7), we have - 7=9(0)−7=0−7=−7
We see that the line y=9x−7 is satisfied by the points A(1,2),B(−1,−16) and C(0,−7).
Therefore, A(1,2),B(−1,−16) and C(0,−7) are solutions of the linear equation y=9x−7 and therefore, lie on the graph of the linear equation y=9x−7.
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