Question

A+B = 10, A-B-2, AB= 24. Find the value.
a)(a²+b²)+2ab

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Answer 1

Answer:

-960

Please thank my ans

Step-by-step explanation:

a+b=10

a=10-b (i)

a-b=2

a=2+b (ii)

from i and ii

10-b=2+b

b+b=10-2

2b=8

b=8/2=4

so, a=10-b

a=10-4=6

(a²-b²)-2ab

(6²-4²)-2*6*4

(36-16)-48

(20)-48

-960

Answer 2

a+b=10--(1)

a-b=2--(2)

(2)implies,a=b+2--(3)

substituting a=b+2 in equation (1) we get

b+2+b=10

2b+2=10

2(1+b)=10

1+b=5

b=4

now,from(3) we get a=6

so (a²+b²)+2ab

=(36+16)+2×24

=52+48

=100