Question

a+b= 10
a-b=6
Find the value of (a square + b sqaure)​

Answer 1

Answer:

68

Step-by-step explanation:

a=8,b=2

a+b=8+2=10

a-b=8-2=6

8×8+2×2= 68

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Answer 2

⠀⠀⠀⠀⠀⠀${\huge{\underbrace{\rm{Question}}}}$

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If a+b= 10 and a-b=6 then find the value of (a²+b²)

⠀⠀⠀⠀⠀⠀⠀${\huge{\underbrace{\rm{Answer}}}}$

Given:

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• a + b = 10

• a – b = 6

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To find:

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find the value of (a²+b²)

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Solution:

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As we know that,

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⠀⠀$\begin{gathered}\star\;{\boxed{\sf{\pink{2(a^{2}+b^{2})=(a+b)^{2}+(a-b)^{2}}}}}\\ \\\end{gathered}$

⠀⠀⠀⠀⠀⠀⠀$\sf{:\implies 2(a^{2}+b^{2})=(a+b)^{2}+(a-b)^{2}}$

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⠀⠀⠀⠀$\sf{:\implies 2(a^{2}+b^{2})=(10)^{2}+(6)^{2}}$

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⠀⠀⠀⠀$\sf{:\implies 2(a^{2}+b^{2})=100+36}$

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⠀⠀⠀⠀$\sf{:\implies 2(a^{2}+b^{2})=136}$

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⠀⠀⠀⠀$\sf{:\implies (a^{2}+b^{2})={\cancel{\dfrac{136}{2}}}}$

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⠀⠀⠀⠀$\begin{gathered}\begin{gathered}:\implies{\underline{\boxed{\sf{\purple{a^{2}+b^{2}=68}}}}}\;\bigstar\\ \\\end{gathered}\end{gathered}$

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⠀⠀⠀⠀$\begin{gathered}\begin{gathered}\bf{\dag}\;{\underline{\sf{\pink{The\:value\:of\:a^{2}+b^{2}=68}}}}\\ \\\end{gathered} \end{gathered}$

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