Question

a+b=10 , ab=21 find$a^{3}+b^{3}$​

Answer 1

Answer:

answer is 370

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Answer 2

◇ Question ◇

a+b=10 , ab=21 find=$a^{3}+b^{3}$.

$\rule{300}2$

Given,

→a+b=10

→ab=21

find = $a^{3}+b^{3}$

○ Solution ○

→ Cubing on both side

$\implies (a+b)^{3}=10^{3} \\ \implies a^3+b^3+3*a*b(a+b)=1000 \\ \implies a^3+b^3+3×21×10=1000 \\ \implies a^3+b^3=1000-630 \\ \implies a^3+b^3=370$

$\rule{300}2$

Hence,

$\large{\bf{\fbox{\fbox{a^3+b^3=370}}}}$