Math, asked by TundAgate500, 1 year ago

a+b=10 and a 2 +b 2 =58, find the value of a 3 +b 3 .

Answers

Answered by TPS
5
a+b = 10
⇒ (a+b)² = 10² 
⇒ a² + b² + 2ab = 100
⇒ 58 + 2ab = 100
⇒ 2ab = 100- 58 =42
⇒ ab = 42/2 = 21

(a+b)³ = a³ + b³ + 3ab(a+b)
⇒ 10³ = a³ + b³ + 3×21×(10)
⇒ 1000 = a³ + b³ + 630
⇒ a³ + b³ = 1000 - 630
⇒ a³ + b³ = 370
Answered by sairockzz
0
a3+b3 is 370 whould been there
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