a+b=10 and ab=16,find the value of a2+ab+b2 and a2+ab+b2
00MuskanSIngh00:
did you mean a sq. and b ssq. by a2 and b2?
Answers
Answered by
33
@
a+b=10
ab=16
(a+b)²=a²+b²+2ab
(10)²=a²+b²+2(16)
100=a²+b²+32
a²+b²=100-32
a²+b²=68
______________
a²+ab+b²
=>68+16
=>84
a²+b²+ab=84
@:-)
a+b=10
ab=16
(a+b)²=a²+b²+2ab
(10)²=a²+b²+2(16)
100=a²+b²+32
a²+b²=100-32
a²+b²=68
______________
a²+ab+b²
=>68+16
=>84
a²+b²+ab=84
@:-)
Answered by
32
Hey there! ^_^
Looks like I can help you.
=======================
(a+b)=10 .....(1)
ab=16 .....(2)
we know
(a+b)² =a²+b²+2ab
substituting values of (1),(2)
10²=a²+b²+2(16)
100= a²+b²+32
100-32= a²+b²
68= a²+b²
Now
a²+b²+ab=68+16=84
a²+b²-ab=68-16=52
hope helped!
Looks like I can help you.
=======================
(a+b)=10 .....(1)
ab=16 .....(2)
we know
(a+b)² =a²+b²+2ab
substituting values of (1),(2)
10²=a²+b²+2(16)
100= a²+b²+32
100-32= a²+b²
68= a²+b²
Now
a²+b²+ab=68+16=84
a²+b²-ab=68-16=52
hope helped!
Similar questions