Question

A+b=10 and ab=24 find the value

Answer 1

Step-by-step explanation:

$(a + b)^{2} = {a}^{2} + {b}^{2} + 2ab$

put value of a+b and ab

${10}^{2} = {a}^{2} + {b}^{2} + 2 \times 24$

${a}^{2} + {b}^{2} = {10}^{2} - 2 \times 24$

$= 100 - 48 = 52$