A+B=10, B-C=3, C×D=2, A+B-C×D=?
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Answered by
1
Answer:
8
Step-by-step explanation:
In this system of equations, B-C=3 is irrelevant.
Replacing the values of A+B and C×D,
10 - 2 = 8
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Answered by
0
Answer:
A+B=10 (given) .....1
B-C=3 (given)
C×D=2 (given) .......2
from 1 nd 2
A+B-(C×D)
10-(2)=8
here,A&B=5
C=2
D=1
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