a + b=11 ab=28 a³+b³
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the correct answer is 407
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(a+b)^2=a^2+b^2+2ab
121=a^2+b^2+56
a^2+b^2=121-56
=65
(a-b)^2=a^2+b^2-2ab
(a-b)^2=65-56
a-b=3
so a=7
b=4
a^3-b^3
=343+64
=407
121=a^2+b^2+56
a^2+b^2=121-56
=65
(a-b)^2=a^2+b^2-2ab
(a-b)^2=65-56
a-b=3
so a=7
b=4
a^3-b^3
=343+64
=407
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