Question

A+B=135 then (1-tanA) (1-tanB)

Answer 1

Answer:

2

Step-by-step explanation:

A+B = 135

Tan(A+B) = Tan 135

// But Tan(A+B) = TanA + TanB / 1 - TanA TanB;

//Tan 135 = Tan(90+45) =  - Cot45 = -1

TanA + TanB / 1 - TanA TanB = - 1

TanA + TanB  = - 1 + TanATanB

TanATanB - TanA - TanB = 1

/Add one on both sides.

TanATanB - TanA - TanB + 1 = 1 +1

(1  - TanB) - TanA(1 - TanB)  = 2

(1 - TanB) ( 1 - TanA) = 2

Answer 2

Answer:

2

Step-by-step explanation:

(1-tamA) (1-tanB) =1-tanA-tanB+tana.tanB

given,

a+b=tan 315

tan(a+b) =tan315

tana+tanb

_________ =tan(360-45)

1-tana.tanb

tana+tanb

_________ =-1

1-tana.tanb

tana+tanb=-1+tanAtanB

tana+tanB-tanA.tanB=-1

-tanB-tanA+tana.tanB=1

add 1

1-tanA-tanB+tanAtanB=2