Math, asked by good1737, 1 year ago

A+B=135°, then (1+cotA)(1+cotB)

Answers

Answered by mathsdude85

14

A+B=135°

cot(A+B)=cot(135°)

cotAcotB-1=-cotA-cotB

1+cotA+cotB+cotAcotB=2

1(1+cotA)+cotB(1+cotA)=2

(1+cotA)(1+cotB)=2

Answered by jsjsjsjjsjs

5

A+B=135°

cot(A+B)=cot(135°)

cotAcotB-1=-cotA-cotB

1+cotA+cotB+cotAcotB=2

1(1+cotA)+cotB(1+cotA)=2

(1+cotA)(1+cotB)=2

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