A+B=135°, then (1+cotA)(1+cotB)
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Answered by
3
A+B=135°
cot(A+B)=cot(135°)
cotAcotB-1=-cotA-cotB
1+cotA+cotB+cotAcotB=2
1(1+cotA)+cotB(1+cotA)=2
(1+cotA)(1+cotB)=2
Answered by
0
A+B=135°
cot(A+B)=cot(135°)
cotAcotB-1=-cotA-cotB
1+cotA+cotB+cotAcotB=2
1(1+cotA)+cotB(1+cotA)=2
(1+cotA)(1+cotB)=2
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