Question

A+b=16
A+c=26
B+d=16
C-d=12
Solve this problem

Answer 1

The values are :

A=14

b=2

c=12

d=0

B=16

Answer 2

The solution of the given system is a=7 , b= 9 , c=19 , d=7 .

Explanation:

Given equations :

a+b=16                (1)

a+c=26               (2)

b+d=16               (3)

c-d=12                (4)

From (1) and (3) , we ahve

$a+b=b+d\Rightarrow\ a=d$

Put d=a in (4) , we get

c-a=12                   (5)

Now , add (2) and (5) , we get

$2c=38\Rightarrow\ c=\dfrac{38}{2}=19$

From (2) , $a+19=26\Rightarrow\ a=26-19=7$

So , a= d= 7

Put value of a in (1) , we get

$7+b=16\Rightarrow\ b=16-7=9$

Hence,  a=7 , b= 9 , c=19 , d=7

# Learn more :

Solve the system of linear equation by substitution.

b = -3a - 7

b = a + 9

Solution: (☐, ☐)

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