A+b=16 a² +b² =124. Ab=
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Solution:
Given a+b=16 ---(1)
a²+b²=124 ----(2)
we know the algebraic identity:
a²+b²+2ab = (a+b)²
=> 124+2ab= 16²
=> 124 + 2ab = 256
=> 2ab = 256 - 124
=> 2ab = 132
=> ab = 132/2
=> ab = 66
Therefore,
ab = 66
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