Question

(a+b)²=144, (a-b)²=4 find (a+b)²+(a-b)²​

Answer 1

Answer: 140

Step-by-step explanation:

since, (a+b)²=144 and (a-b)²=4

we can subtract 4 from 144

which will give u 140 as the difference(answer)

Hope it helps <33333

Answer 2

Answer:

The answer is $(a+b)^{2}+(a-b)^{2}=148$

Step-by-step explanation:

We have given the values $(a+b)^{2} =144$ and $(a-b)^{2} =4$. The question is to find the value of $(a+b)^{2}+(a-b)^{2}$.

Now put the value of $(a+b)^{2}$ and $(a-b)^{2}$ in $(a+b)^{2}+(a-b)^{2}$. Then the equation will be,

$(a+b)^{2}+(a-b)^{2}=144+4$

When we add, we combine numbers together to find sum. The numbers that we are adding are called addends. Here the addends are 144 and 4. To add these numbers write the numbers one below the other, then add the numbers in ones column first then the tens column, and finally the hundreds column. That is,

                                 $\begin{aligned}144+\\\dfrac{4}{148}\end{aligned}$

So, this is the answer for the question.