Question

A:B=2:3 , B:C = 4:5 and C:D = 3:7 then find the share of A in 1050 rupees​

Answer 1

Answer:

Sum of the ratio terms is (1 + 3 + 4) = 8

We have the following:

A's share = Rs 5600 ×

1

8

=Rs

5600

8

= Rs 700

B's share = Rs 5600 ×

3

8

= Rs 700 × 3 = Rs 2100

C's share = Rs 5600 ×

4

8

=Rs 700 ×4 = Rs 2800

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

A:B = 2 : 3

A:B = 2 : 3B:C = 4 : 5

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.C = 6 x 3 x 5 = 90

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.C = 6 x 3 x 5 = 90D is the product of all terms appearing under column (2).

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.C = 6 x 3 x 5 = 90D is the product of all terms appearing under column (2).D = 3 x 5 x 7 = 105

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.C = 6 x 3 x 5 = 90D is the product of all terms appearing under column (2).D = 3 x 5 x 7 = 105=> A:B:C:D = 48:72:90:105

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.C = 6 x 3 x 5 = 90D is the product of all terms appearing under column (2).D = 3 x 5 x 7 = 105=> A:B:C:D = 48:72:90:105You can find ratio between any two or three variables from above.

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.C = 6 x 3 x 5 = 90D is the product of all terms appearing under column (2).D = 3 x 5 x 7 = 105=> A:B:C:D = 48:72:90:105You can find ratio between any two or three variables from above.A:D = 48:105 = 16:35

A:B = 2 : 3B:C = 4 : 5C:D = 6 : 7A is the product of all terms appearing under column (1).A = 2 x 4 x 6 = 48B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.B = 4 x 6 x 3 = 72C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.C = 6 x 3 x 5 = 90D is the product of all terms appearing under column (2).D = 3 x 5 x 7 = 105=> A:B:C:D = 48:72:90:105You can find ratio between any two or three variables from above.A:D = 48:105 = 16:35If A:B, B:C, C:D, D:E, E:F, F:G, G:H, H:I is given, we can find A:B:C:D:E:F:G:H:I using above method.