Question

(a-b)^2+6(a-b)+8 factorise it

Answer 1

$(a - b) {}^{2} + 4(a - b) + 2(a - b) + 8$

$(a - b)((a - b) + 4) + 2((a - b) + 4)$

$(a - b)(a - b + 4)$
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Radhe Radhe

Answer 2

Hello friends!!!

Here is your answer :

$= > {(a - b)}^{2} + 6(a - b) + 8$


Let ( a - b)= x

$= > {x}^{2} + 6x + 8$

$= > {x}^{2} + (4 \: + \: 2)x + 4 \times 2$


$= > {x}^{2} + 4x + 2x + 4 \times 2$


$= >x(x + 4) + 2(x + 4)$


$= > (x + 4)(x + 2)$


Putting the value of x.

$= > (a - b + 4)(a - b + 2)$


Hope it helps you

^_^