Question

(a+b)^2=99,(a-b)^2=3 হলে a^2+b^2=?​

Answer 1

so finally, Answer is 51 !

Answer 2

সমাধান:

দেওয়া আছে:

→ (a + b)² = 99 – (i)

→ (a - b)² = 3 – (ii)

(i) এবং (ii) যোগ করলে পাব:

→ (a + b)² + (a - b)² = 99 + 3

→ a² + 2ab + b² + a² - 2ab + b² = 102

→ 2a² + 2b² = 102

→ 2(a² + b²) = 102

→ a² + b² = 51.

★ সুতরাং, a² + b² এর মান হল 51.

আরো জানুন:

• (a + b)² = a² + 2ab + b²
• (a - b)² = a² - 2ab + b²
• a² - b² = (a + b)(a - b)
• (a + b)³ = a³ + 3ab(a + b) + b³
• (a - b)³ = a³ - 3ab(a - b) - b³
• a³ + b³ = (a + b)(a² - ab + b²)
• a³ - b³ = (a - b)(a² + ab + b²)
• (x + a)(x + b) = x² + (a + b)x + ab
• (x + a)(x - b) = x² + (a - b)x - ab
• (x - a)(x + b) = x² - (a - b)x - ab
• (x - a)(x - b) = x² - (a + b)x + ab