(a-b)^2=a^2-2ab+b^2
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Answered by
1
Answer:
(a-b)²=a²-b (a-b)- b (a-b) -b²
= a²- ab + b²-ab +b²-b²
=a²-2ab+b²
hence, geometrically we proved the indentify (a-b)=a²-2ab+b²
Step-by-step explanation:
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Answered by
4
Step-by-step explanation:
Step 1: Draw a square ACDF with AC=a units.
Step 2: Cut AB=b units so that BC=(a−b) unts.
Step 3: Complete the squares and rectangle as shown in the diagram.
Step 4: Area of yellow square IDEO= Area of square ACDF− Area of rectangle GOFE− Area of rectangle BCIO− Area of red square ABOG
Therefore, (a−b)
2
=a
2
−b(a−b)−b(a−b)−b
2
= a
2
−ab+b
2
−ab+b
2
−b
2
= a
2
−2ab+b
2
Hence, geometrically we proved the identity (a−b)
2
=a
2
−2ab+b
2
.
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