Question

(a+b)² - (a-b)² = 4ab ​

Answer 1

ANSWER:

L.H.S=

(a+b)²-(a-b)²

= a²+2ab+b² - a²+2ab-b²

= 2ab + 2ab

= 4ab

= R.H.S

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Answer 2

$\huge\bold{Answer}$

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LHS

${(a + b)}^{2} - {(a - b)}^{2} \\ \\ ({a}^{2} + {b}^{2} + 2ab )\: - ( {a}^{2} + {b}^{2} - 2ab) \\ \\ {a}^{2} + {b}^{2} + 2ab - {a}^{2} - {b}^{2} + 2ab \\ \\ \\ now \: {a}^{2} \: and \: {b}^{2} will \: cancelled \: out \: and \: 2ab + 2ab \: remains \: which \: on \: addition \: give \: 4ab \\ \\ \\ 2ab + 2ab \: = 4ab$

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