Question

(a+b)^2/(a-b)^2 = 9 then find the value of (a+b)/(a-b)​

Answer 1

Answer:

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Step-by-step explanation:

$\frac{(a+b)^2}{(a-b)^2} = 9 \\ \\rooting \: \: both \: \: sides \\ \\ \sqrt{ \frac{(a+b )^2 }{(a-b)^2} } = \sqrt{9} \\ \\ \frac{ \sqrt{(a+b)^2} }{ \sqrt{} (a - b)^2} = \sqrt{9} \\ \\ \frac{a+b}{a - b} = 9$

Answer 2

Answer:

+/- 3

Step-by-step explanation

√(a+b)²            = .      √9 .                  Taking square root of full equation easy

√(a-b)²

(a+b)                = .    +/- 3

(a-b)

Hence this is your answer plus or minus 3