(a + b)² + (a - b)² =_________
a) a² + b² b) a² - b² c) 2a² + 2b² d) 2a² - 2b²
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Answer:
C is the right solution.
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Step-by-step explanation:
What is (a+b) ²+(a-b) ²?
Solution :
[ A^B means “ A ” to the power of “ B ” ]
Given , (a+b)^2+ (a-b)^2 = ?
We know that ,
(a+b)^2 = a^2 + b^2 + 2ab ———equation 1
We also know that ,
(a-b)^2 = a^2 + b^2 - 2ab ———equation 2
So, in order to find sum of (a+b)^2 and (a-b)^2 ,
i.e (a+b)^2 + ( a-b) ^2 ,
we need to add equations 1 and 2 .
So , by adding equations 1 and 2 , we get ,
=> (a+b)^2 + (a-b)^2 = a^2 + b^2 + a^2 + b^2
= 2(a^2 + b^2 )
As, ( +2ab ) and (—2ab ) terms get cancelled.
Therefore ,
(a+b)^2 + ( a-b)^2 = 2(a^2 + b^2 ) .
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