Question

(a+b)^2 + (a-b)^2
Answer fast...​

Answer 1

${(a + b)}^{2} + {(a - b)}^{2}$

$({a}^{2} + {b}^{2} + 2ab) +$

$( {a}^{2} + {b}^{2} - 2ab)$

${a}^{2} + {b}^{2} + 2ab+$

${a}^{2} + {b}^{2} - 2ab$

2ab will be cancelled 'cause both are having opposite signs...

${a}^{2} + {b}^{2} + {a}^{2} + {b}^{2}$

$2 {a}^{2} + 2{b}^{2} (answer)$

Answer 2

Answer:

$2(a^{2} +b^{2} )$

Step-by-step explanation:

$(a+b)^{2} +(a-b)^{2} \\=a^{2} +b^{2} +2ab+a^{2} +b^{2} -2ab\\=2a^{2} +2b^{2} \\=2(a^{2} +b^{2} )$