Question

(a+b)²+(a-b)²
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Answer 1

Answer:

[ A^B means “ A ” to the power of “ B ” ]

Given , (a+b)^2+ (a-b)^2 = ?

We know that ,

(a+b)^2 = a^2 + b^2 + 2ab ———equation 1

We also know that ,

(a-b)^2 = a^2 + b^2 - 2ab ———equation 2

So, in order to find sum of (a+b)^2 and (a-b)^2 ,

i.e (a+b)^2 + ( a-b) ^2 ,

we need to add equations 1 and 2 .

So , by adding equations 1 and 2 , we get ,

=> (a+b)^2 + (a-b)^2 = a^2 + b^2 + a^2 + b^2

= 2(a^2 + b^2 )

As, ( +2ab ) and (—2ab ) terms get cancelled.

Therefore ,

(a+b)^2 + ( a-b)^2 = 2(a^2 + b^2 ) .

Step-by-step explanation:

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Answer 2

Answer:

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