(a+b)²-(a-b)² Solve this pleas
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Answer:
Solution….
…..(a+b)²-(a-b)²
…..a²+b²+2ab - (a²+b²-2ab)
…..a²+b²+2ab -a²-b²+2ab
…..2ab+2ab
…..4ab..Ans……
Step-by-step explanation:
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Answered by
1
Answer:
Step-by-step explanation:
Solution :
___________________________
[ A^B means “ A ” to the power of “ B ” ]
Given , (a+b)^2+ (a-b)^2 = ?
We know that ,
(a+b)^2 = a^2 + b^2 + 2ab ———equation 1
We also know that ,
(a-b)^2 = a^2 + b^2 - 2ab ———equation 2
So, in order to find sum of (a+b)^2 and (a-b)^2 ,
i.e (a+b)^2 + ( a-b) ^2 ,
we need to add equations 1 and 2 .
So , by adding equations 1 and 2 , we get ,
=> (a+b)^2 + (a-b)^2 = a^2 + b^2 + a^2 + b^2
= 2(a^2 + b^2 )
As, ( +2ab ) and (—2ab ) terms get cancelled.
Therefore ,
(a+b)^2 + ( a-b)^2 = 2(a^2 + b^2
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