Question

(a+b)2 -a+b whole square

Answer 1

Hey mate !!

Here's your answer !!

We know the identities that,

( a + b )² = a² + 2ab + b²

So According to the question, we get,

( a + b )² - ( a + b )²

a² + b² + 2ab - ( a² + b² + 2ab )

=> a² + b² + 2ab - a² - b² - 2ab

All the terms get cancelled. Hence we get 0

So The answer is 0.

Hope my answer helps !!

Cheers !!

Answer 2

HEY HERE IS YOUR ANSWER.

$as \: \: we \: \: know \\ \\ (a + b) ^{2} = {a}^{2} + {b }^{2} + 2ab \\ \\ hence \: \: {(a + b)}^{2} - (a + b) ^{2} \\ \\ ({a}^{2} + {b}^{2} + 2ab) - ( {a}^{2} + {b}^{2} + 2ab) \\ \\ {a}^{2} + {b}^{2} + 2ab - {a}^{2} - {b}^{2} -2ab \\ \\ 2ab - 2ab = 0 \: \: \: which \: is \: \\ the \: final \: answer$

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