Question

(a-b)^2+(a-c)^2=(b-c)^2
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Multiple choice pic attached

Answer 1

Step-by-step explanation:

B) Equation is valid when $a = b$ because,

${(a - b)}^{2} + {(a - c)}^{2} = {(b - c)}^{2}$

if $a = b$ then,

${(a - a)}^{2} + {(a - c)}^{2} = {(a - c)}^{2}$

${(a - c)}^{2} = {(a - c)}^{2}$

Answer 2

Answer:

b and c

Step-by-step explanation:

a^2+b^2-2ab+a^2+c^2-2ac=b^2+c^2-2bc

2a^2-2ab-2ac+2bc=0

a^2-ab-ac+bc=0

so according to options b and c are correct