Question

(a-b)² = a²-2ab+b²
say how it's expanded
no spam..​

Answer 1

• $\huge{\underline{\underline{\boxed{\sf{\red{Answer\: ࿐}}}}}}$
• The distributive property says for numbers A, B, C,
• A × (B + C) = (A × B) + (A × C)
• How does this apply to (a + b) × (a + b)?
• a + b is just a number, so it is valid to treat (a + b) as A, B, or C in the distributive property, because the property *always* works when A, B, C are numbers.
• So let's connect our expression to the distributive property, by setting a and b to terms with A, B, C.
• A = a + b
• B = a
• C = b
• After plugging in these values,
• A × (B + C) = (A × B) + (A × C) becomes
• (a + b) × (a + b) = ((a + b) × a) + ((a + b) × b)
• Since the order of multiplication does not matter, we can rewrite the right side of that equation…
• ( a + b) × (a + b) = (a × (a + b)) + (b × (a + b))
• Now, using the distributive property more simply,
• (a + b) × (a + b) = (a×a + a×b) + (b×a + b×b)
• The parentheses on the right side do not change order of operations, because the order that we add all of the multiplied terms up does not matter, so
• (a + b) × (a + b) = a×a + a×b + b×a + b×b
• Of course, b×a can be rewritten as a×b, so
• (a + b) × (a + b) = a×a + a×b + a×b + b×b
• Now we can combine the two like-terms of a×b
• (a + b) × (a + b) = a×a + 2×a×b + b×b
• Which is more common written as
• (a+b)2=a2+2ab+b2

Answer 2

Step-by-step explanation:

ms . ghost here is ur answer

Good night may ur dreams come true