Question

(a+b)²=a²+6a+9
value of b?​

Answer 1

$\huge\underline\mathfrak\blue{answer}$

give:-

=>(a+b)²=a²+6a+9

=> a²+b²+2ab=a²+6a+9

=> a(2b-6)=(9-b)²

$= > a = \frac{(9 - {b})^{2} }{(2b - 6)}$

✌️this is your answer✌️

Answer 2

$\huge\underline\mathfrak\blue{answer}$

give:-

=>(a+b)²=a²+6a+9

=> a²+b²+2ab=a²+6a+9

=> a(2b-6)=(9-b)²

= > a = \frac{(9 - {b})^{2} }{(2b - 6)}=>a=

(2b−6)

(9−b)

2

✌️this is your answer✌️