Question

(a-b)2+(b-c)2+(c-a)2=0​

Answer 1

Answer:

Solution = ( a - b) ² + ( b- c) ² + ( c - a)²

( we know ( a+ b) ² = a² + 2ab + b² and

( a - b) = a² - 2ab + b² )

Let's solve

= a² + 2ab + b² + b² - 2bc + c² + c² -2ac + a²

= 2a²+ 2b² + 2c² + 2ab - 2bc - 2ac