Question

(a-b)²-(b-c)²
factorise​

Answer 1

Answer:

${(a - b)}^{2} - {(b - c)}^{2} \\ \\ \\ = {a}^{2} + {b}^{2} - 2ab - ( {b}^{2} + {c}^{2} - 2bc) \\ \\ \\ = {a}^{2} \: { \cancel{+ {b}^{2} }} - 2ab \: \: { \cancel{ - {b}^{2} }} - {c}^{2} + 2bc \\ \\ \\ { \large{ \purple{ = {a}^{2} - {c}^{2} - 2ab + 2bc}}}$

Answer 2

Answer:

(a -b)² - ( b - c)²

= a² - 2ab + b² - (b² - 2bc + c²)

= a² - 2ab + b² - b² - 2bc + c²

= a² - 2 (ab+bc) + c²

hope it helps u