(a-b) ²- (b-c) ² factorise it by suitable method
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
Lets proceed
(a+b+c) ^2
=(a+b+c)* (a+b+c) ;
=a*a + a*b + a*c + b*a + b*b + b*c + c*a + c*b + c*c;
=a^2 + ab + ac + ba + b^2 + bc + ca + cb + c^2;
=a^2 + b^2 +c^2 + ab +ba +bc +cb + ac + ca ;
=a^2 + b^2 + c^2 + 2ab + 2bc + 2ca;
So here we got the final result.
Therefore,
(a+b+c) ^2 = a^2 +b^2 + c^2 + 2ab + 2bc + 2ca.
Thank you.
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