(a-b) ² - (b-c) ² solve
Answers
Answered by
11
hey mate here is your answer
(a-b)^2 -(b-c)^2
a^2+b^2-2ab -b^2-c^2+2bc
a^2-c^2+2b(-a+c)
hope this may help you
(a-b)^2 -(b-c)^2
a^2+b^2-2ab -b^2-c^2+2bc
a^2-c^2+2b(-a+c)
hope this may help you
Answered by
15
(a-b)^2-(b-c)^2
=a^2+b^2-2ab-b^2-c^2+2bc
=a^2-c^2-2ab-2bc
=(a-c)(a+c)-2b(a-c)
=(a-c)[a+c-2b]
Your answer
=a^2+b^2-2ab-b^2-c^2+2bc
=a^2-c^2-2ab-2bc
=(a-c)(a+c)-2b(a-c)
=(a-c)[a+c-2b]
Your answer
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