Question

(a-b)2/(b-c)(c-a) + (b-c)2/(c-a)(a-b) + (c-a)2/(a-b)(b-c)

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Answer 1

Is it from English?

(a-b)^2/(b-c)(c-a)+(b-c)^2/(c-a)(a-b)+(c-a)^2/(a-b)(b-c)

=(a^2+b^2-2ab)/(bc-ab-c^2+ac)+(b^2+c^2-2bc)/(ac-bc-a^2+ab)+(c^2+a^2-2ac)/(ab-ac-b^2+bc)

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