Question

| a^+b^|=√2
Find angle between a^ and b^

Answer 1

Answer:

Explanation:

A = |A|

B = |B|

 

|A + B| = √(A2 + B2 + 2ABcosθ)

 

|A - B| = √(A2 + B2 - 2ABcosθ)

 

|A + B| = |A - B| ⇒

 

√(A2 + B2 + 2ABcosθ) = √(A2 + B2 - 2ABcosθ)

 

Square both sides.

 

A2 + B2 + 2ABcosθ = A2 + B2 - 2ABcosθ

 

2ABcosθ = -2ABcosθ

 

If A ≠ 0 and B ≠ 0, then

 

cosθ = -cosθ ⇒

 

cosθ = 0 ⇒ θ = 90°

Answer 2

Answer:

answer is 90 degrees as shown in figure