Question

(a+b) (2 + i) = b + 1 + (10 + 2a)i
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Answer 1

Step-by-step explanation:

maybe it helps you,and tell me thanks

Answer 2

$\mathfrak{ \huge{ \green{✤SolutioN!}}}$

$\sf{(a+b) (2 + i) = b + 1 + (10 + 2a)i}$

$\sf{ = > 2a + ai + 2b + bi = b + 1 + (10 + 2a)i}$

$\sf{ = > (2a + 2b) + (a + b)i = b + 1 + (10 + 2a)i}$

$\sf{ \blue{Equation \: the \: real \: and \: the \: imagenery \: parts, }}$

$\sf{2a + 2b = b + 1 - - - - - - - - - - (1)}$

$\sf{a + b = 10 + 2a - - - - - - - - - - (2)}$

$\sf{ \bold{From \: (1)}}$

$\sf{2b - b = 1 - 2a}$

$\sf{b = 1 - 2a - - - - - - - - - - (3)}$

$\sf{ \bold{From \: (2)}}$

$\sf{b = 10 + 2a - a}$

$\sf{b = 10 + a - - - - - - - - - - (4)}$

$\sf{ \bold{From \: (3) \: and \: (4)}}$

$\sf{1 - 2a = 10 + a}$

$\sf{ = > 1 - 10 = a + 2a}$

$\sf{3a = - 9}$

$\sf{ = > a = - 3}$

$\sf{ \blue{Substituting \: a \: in \: equation \: 3}}$

$\sf{b = 10 + a}$

$\sf{b = 10 - 3}$

$\sf{b = 7}$

$\sf{ \green{ \underline{Hence, \: a = - 3 \: and \: b = 7}}}$

Hope you this helps you mate✌