Question

(a+b) (2+i)=b+1+(10+2ai)i​

Answer 1

2a+2b+ai+bi=b+1+(10+2a)i

2a+b+ai+bi=1+10i+2ai

2a+b+bi=1+10I+ai

(2a+b)+bi=1+(10+a)i

equating the imaginary & real numbers

2a+b=1,

10+a=b

2a+b=1

a-b=10

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3a =-9

a=-3

2(-3)+b=1

-6+b=1

b=7

a=-3 & b=7