Question

A+b =π/2 then tanb + 2tan a-b=

Answer 1

Answer:

hello is the answer of this question

Step-by-step explanation:

answer we get here is tanA

when you tanA is the correct answer

Answer 2

Answer:

tanb + 2tan a-b=  tana

Step-by-step explanation:

Given

a+b = $\frac{\pi }{2}$

Recall the formulas

tan  $\frac{\pi }{2}$ = not defined

tan(A+B) =$\frac{tanA +tanB}{1-tanAtanB}$

tan(A-B) =$\frac{tanA -tanB}{1+tanAtanB}$

Solution

a+b = $\frac{\pi }{2}$

tan(a+b) = tan $\frac{\pi }{2}$ = not defined

$\frac{tana +tanb}{1-tanatanb}$ = not defined

⇒1-tantanb = 0

⇒ tana×tanb = 1

tan b+2tan(a-b) = tanb +2× $\frac{tana -tanb}{1+tanatanb}$

=tan b + 2×$\frac{tana -tanb}{1+1}$

= tanb +tana-tanb

= tana

∴tanb + 2tan a-b=  tana

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