A×b=20,bsquare×c=48,a+b×c=17, find the value of a
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A=5
B=4
C=3
Then, A+B multiply by C
5+4(3)
5+12
17
Answered by
0
Answer:
85/12
Step-by-step explanation:
a×b=20
a=20/b
bsq×c=48
c=48/bsq
a+b×c=
substitute all values
20/b+b×48/bsquare
20/b+48/b
68/b=17
b=68/17
a×68/17=20
a=5
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